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Algebra Difficulty: Easy

$g (x) = 11 x + 4$

For the given linear function $g$ , which table shows three values of $x$ and their corresponding values of $g (x)$ ?

$x$	$g (x)$
$negative 1$	$7$
$0$	$11$
$1$	$15$

$x$	$g (x)$
$negative 1$	$negative 4$
$0$	$0$
$1$	$4$

$x$	$g (x)$
$negative 1$	$negative 7$
$0$	$4$
$1$	$15$

$x$	$g (x)$
$negative 1$	$negative 11$
$0$	$0$
$1$	$11$

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Explanation

Choice C is correct. Each of the tables shows the same three values of $x$ : $negative 1$ , $0$ , and $1$ . Substituting $negative 1$ for $x$ in the given function yields $g (- 1) = 11 (- 1) + 4$ , or $g (- 1) = - 7$ . Therefore, when $x = - 1$ , the corresponding value of $g (x)$ is $negative 7$ . Substituting $0$ for $x$ in the given function yields $g (0) = 11 (0) + 4$ , or $g left parenthesis 0 right parenthesis equals 4$ . Therefore, when $x equals 0$ , the corresponding value of $g (x)$ is $4$ . Substituting $1$ for $x$ in the given function yields $g (1) = 11 (1) + 4$ , or $g left parenthesis 1 right parenthesis equals 15$ . Therefore, when $x equals 1$ , the corresponding value of $g (x)$ is $15$ . The table in choice C shows $negative 7$ , $4$ , and $15$ as the corresponding value of $g (x)$ for x-values of $negative 1$ , $0$ , and $1$ , respectively. Therefore, the table in choice C shows three values of $x$ and their corresponding values of $g (x)$ .

Choice A is incorrect. This table shows three values of $x$ and their corresponding values of $g (x)$ for the linear function $g (x) = 4 x + 11$ .

Choice B is incorrect. This table shows three values of $x$ and their corresponding values of $g (x)$ for the linear function $g left parenthesis x right parenthesis equals 4 x$ .

Choice D is incorrect. This table shows three values of $x$ and their corresponding values of $g (x)$ for the linear function $g left parenthesis x right parenthesis equals 11 x$ .