sat suite question viewer
In the given system of equations, is a constant. If the system has no solution, what is the value of ?
Explanation
The correct answer is . A system of two linear equations in two variables, and , has no solution if the lines represented by the equations in the xy-plane are distinct and parallel. Two lines represented by equations in standard form , where , , and are constants, are parallel if the coefficients for and in one equation are proportional to the corresponding coefficients in the other equation. The first equation in the given system, , can be written in standard form by adding to both sides of the equation, which yields , or . Multiplying each term in this equation by yields . The second equation in the given system, , can be written in standard form by subtracting and from both sides of the equation, which yields . Multiplying each term in this equation by yields . The coefficient of in the first equation, , is equal to the coefficient of in the second equation, . For the lines to be parallel, and for the coefficients for and in one equation to be proportional to the corresponding coefficients in the other equation, the coefficient of in the second equation must also be equal to the coefficient of in the first equation. Therefore, . Dividing both sides of this equation by yields , or . Therefore, if the given system of equations has no solution, the value of is . Note that 7/2 and 3.5 are examples of ways to enter a correct answer.